Tentukan turunan pertama dari fungsi x-5 / x+5

h(x)= x-5
h'(x)= 1

g(x)= x+5
g'(x)= 1

f'(x)= [h'(x)•g(x) - h(x)•g'(x)] / [g(x)]²
f'(x)= [1•(x+5) - (x-5)•1] / (x+5)²
f'(x)= x+5-x+5 / x²+10x+25
f'(x)= 10/x²+10x+25

Materi : Kalkulus
Bahasan : Turunan Fungsi
Jawaban : [tex]\frac{10}{(x+5)^{2} } [/tex]

Langkah - langkah :
[tex]( \frac{f}{g} )' = \frac{f'g-g'f}{g^{2} } \\ \\ (\frac{x - 5}{x + 5} )' = \frac{1(x+5) - 1(x-5)}{(x+5)^{2} } \\ \\ (\frac{x - 5}{x + 5} )' = \frac{x + 5 - x + 5}{(x+5)^{2} } \\ \\ (\frac{x - 5}{x + 5} )' = \frac{10}{(x+5)^{2} } [/tex]