Bantu jawab pakai cara soal nomor 19-21

19][
F = 20 N
∆x = 5 cm = 5×10⁻² m
Ep = __?

Energi potensial
Ep = ½ F ∆x
Ep = ½ • 10 • 5×10⁻²
Ep = 0,25 J ← jwb



20][
Ep_,benda → Ek_benda → Ep_pegas

Ep_pegas = Ep_benda
½ k ∆x² = m g h
∆x² = 2 m g h / k
∆x = √(2 m g h / k) ← jwb

jika lebih teliti
½ k ∆x² = m g (h + ∆x)



21][
ω = 2 rad/s
r = 5 cm
V = __?

kecepatan linear
V = ω r
V = 2 • 5
V = 10 cm/s = 0,1 m/s ← jwb

Jawaban di lampiran yaaa