Bantu jawab pakai cara soal nomor 22-24

22][
ma = 3 kg. va = 10 m/s
mb = 3 kg. vb = 0
∆Ek = __?

Energi kinetik yang hilang
∆Ek = ½ [ma mb / (ma + mv)] va²
∆Ek = ½ [2 • 3 / (2+3)] • 10²
∆Ek = 60 J ← jwb


23][
mb = 1 kg
mp = 10 gr
vp = 110 m/s
g = 10 m/s²
h = __?

kenaikan tinggi balok+peluru
vp = [(mp + mb) / mp] √(2 g h)
110 = [(1 + 0,01) / 0,01) √(2 • 10 • h)
110 = 101 √(20 h)
(110/101)² = 20 h
h = 0,059 m ← jwb


24][
persamaan gerak rotasi
Σ τ = I α
T R = ½ m R² • a/R
T = ½ m a

persamaan gerak translasi
Σ F = m a
mg - T = ma
mg - ½ ma = ms
mg = 3/2 ma
a = ⅔ g ← jwb

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