yuk bantu saya jawab

[tex]\displaystyle A+B+C=180^\circ\\45^\circ+75^\circ+C=180^\circ\\C=60^\circ\\\\\frac{a}{\sin A}=\frac{c}{\sin C}\\\frac{2\sqrt2}{\sin45^\circ}=\frac{c}{\sin60^\circ}\\\frac{2\sqrt2}{\frac12\sqrt2}=\frac{c}{\frac12\sqrt3}\\\frac{2}{1}=\frac{c}{\sqrt3}\\2\sqrt3=c\\\\L=\frac12ac\sin B\\L=\frac12\cdot2\sqrt2\cdot2\sqrt3\sin75^\circ\\L=\frac12\cdot2\sqrt2\cdot2\sqrt3\cdot\frac{\sqrt6+\sqrt2}{4}\\L=\frac12\cdot\sqrt6\cdot(\sqrt6+\sqrt2)\\L=\frac12(6+\sqrt{12})\\L=\frac12(6+2\sqrt{3})[/tex]
[tex]\displaystyle \boxed{\boxed{L=3+\sqrt{3}\,\text{cm}^2}}[/tex]