tolong bagi yg tahu caranya..bagaimana??

1) integral (1 - x)√x dx
= Integral (1 - x) x^1/2 dx
= Integral (x^1/2 - x^3/2) dx
= 1/(3/2) x^3/2 - 1/(5/2) x^5/2 + C
= 2/3 x^3/2 - 2/5 x^5/2 + C
= 2/3 x√x - 2/5 x^2 √x + C

2) integral (x^3 + 5x^2 - 4)/x^2 dx
= Integral (x^3 + 5x^2 - 4) x^-2 dx
= Integral (x + 5 - 4x^-2) dx
= 1/2 x^2 + 5x - 4/(-1) x^-1 + C
= 1/2 x^2 + 5x + 4/x + C

1. ∫ √x-x√x dx = ∫x^1/2 - x^3/2 dx
=>>>>> 1/ 2/2+1/2 x^1/2+1 - 1/ (2/2+3/2) x^5/2=
=>>> 2/3 x^3/2 - 2/5 x^5/2 +C

2.∫x+5-4x^-2 dx
==>>> 1/2x² +5x -4/-2+1 x^-2+1 + C
=>>>>> 1/2x²+5x +4 x^-1 + C

semoga membantu :)