tolong dibantu ya soal MTK poltekes

4. ²㏒x + ²㏒y³ = 13
    ²㏒xy³ = ²㏒[tex] 2^{13} [/tex] 
    xy³ = [tex] 2^{13} [/tex]
    ²㏒x - ²㏒y = 5
    ²㏒x/y = ²㏒[tex] 2^{5} [/tex] 
    x/y =[tex] 2^{5} [/tex]
    x =[tex] 2^{5} [/tex] y
    
    xy³ = [tex] 2^{13} [/tex]
    [tex] 2^{5} [/tex] .y.y³ = [tex] 2^{13} [/tex]
    [tex] y^{4} [/tex] = [tex] 2^{8} [/tex]
    y = 2²
    y = 4
    x= 32y
      = 32.4
      = 128
x+y = 132

3) x^2 - (p - 2)x + p + 1 = 0 mempunyai akar yang sama jika D = 0
b^2 - 4ac = 0
(-(p - 2))^2 - 4(1)(p + 1) = 0
p^2 - 4p + 4 - 4p - 4 = 0
p^2 - 8p = 0
p(p - 8) = 0
p = 0 atau p = 8

4) 2logx + 2logy^3 = 13 => 2logx + 3 . 2logy = 13
2logx - 2logy = 5

Misal 2logx = p dan 2logy = q
p + 3q = 13
p - q = 5
---------------- --
.... 4q = 8 ==> q = 2

p - q = 5 => p - 2 = 5 => p = 7

q = 2 => 2logy = 2log2^2 => y = 2^2 = 4
p = 7 => 2logx = 2log2^7 => x = 2^7 = 128
x + y = 128 + 4 = 132