Matematika

Pertanyaan

Tolong jawab nomor 4D :)
Tolong jawab nomor 4D :)

1 Jawaban

  • 4d)
    (x - 3)² + (x + 1)² = (x - 2)² + (x + 3)²
    {(x - 3) × (x - 3)} + {(x + 1) × (x + 1)} = {(x - 2) × (x - 2)} + {(x + 3) × (x + 3)}
    {x² - 3x - 3x + 9} + {x² + x + x + 1} = {x² - 2x - 2x + 4} + {x² + 3x + 3x + 9}
    (x² - 6x + 9) + (x² + 2x + 1) = (x² - 4x + 4) + (x² + 6x + 9)
    x² + x² - 6x + 2x + 9 + 1 = x² + x² - 4x + 6x + 4 + 9
    2x² - 4x + 10 = 2x² + 2x + 13
    2x² - 4x + 10 - (2x² + 2x + 13) = 0
    2x² - 4x + 10 - 2x² - 2x - 13 = 0
    2x² - 2x² - 4x - 2x + 10 - 13 = 0
    -6x - 3 = 0
    6x = -3
    x = -3 ÷ 6
    x = [tex] -\frac{1}{2} [/tex]

    HP ={[tex]-\frac{1}{2} [/tex]}