1. nilai dari 216 pangkat 1/2 - (16) pangkat 1/4 + (125) pangkat 2/3 2. bentuk sederhana dari (3√7+5) (4√7-2) 3. (64)^2/3 . (125)^1/6 per (32)^2/5 . (5)^1/2

1. 216= 6^3 =2^3*3^3
16=2^4
125=5^3
maka √6^2*6 - 2^4/4 +5^3(2/3)
= 6√6-2 + 25
= 23 =6√6

2.4√7(3√7) - 3√7(2) +20√7 -10
= 12(7)-6√7 +20√7-10
=>>> 84-10+20√7-6√7 = 74 +14√7
3. 64= 4^3 ; 125= 5^3 ; 32=2^5
4^3(2/3) * 5^3/6 / 2^10/5 * √5
= 4² * √5 / 4 √5
= 4

1) 216^(1/2) - 16^(1/4) + 125^(2/3)
= √216 - 2^4(1/4) + 5^3(2/3)
= √36 √6 - 2^1 + 5^2
= 6√6 - 2 + 25
= 6√6 + 23

2) (3√7 + 5)(4√7 - 2)
= (12.7 - 6√7 + 20√7 - 10)
= 84 - 10 + 14√7
= 74 + 14√7

3) (64^(2/3) . 125^(1/6)) / (32^(2/5) . 5^(1/2))
= (4^3(2/3) . 5^3(1/6)) / (2^5(2/5) . 5^(1/2))
= (4^2 . 5^(1/2)) / (2^2 . 5^(1/2))
= 16 / 4
= 4