tolong jawab soal di bawah

7x- 14/5x²y³  ×  x² - yx/3x-6
= (7x-14)(x²-yx) / (5x²y³)(3x-6)
= 7x³ - 7yx² - 14x² - 14yx / 15 x³y³ - 30x²y³
yang seterusnya mohon dihitung sendiri

[tex] \frac{7x-14}{5 x^{2} y^{3} } [/tex]×[tex] \frac{ x^{2} -yx}{3x-6} [/tex] = [tex] \frac{7(x-2)}{5 x^{2} y^{3} } [/tex]×[tex] \frac{x(x-y)}{3(x-2)} = \frac{7(x-y)}{15x y^{3} } = \frac{7x-7y}{15x y^{3} } [/tex]