Dua buah benda memiliki muatan listrik masing masing sebesar+16C dan -12C.jarak antara kedua muatan 4cm dan nilai konstanta 9.10'9 Nmยฒ/Cยฒ.berapakah besar gaya

[tex]\displaystyle Q_1=+16\,\text{C}\\Q_1=-12\,\text{C}\\k=9\cdot10^9\,\text{Nm}^2/\text{C}^2\\r=4\cdot10^{-2}\,\text{m}\\\\F=?\\\\F=\frac{kQ_1Q_2}{r^2}\\F=\frac{9\cdot10^9\cdot16\cdot(-12)}{(4\cdot10^{-2})^2}\\F=\frac{9\cdot10^9\cdot16\cdot(-12)}{16\cdot10^{-4}}\\F=\frac{9\cdot10^9\cdot(-12)}{10^{-4}}\\F=9\cdot10^{13}\cdot(-12)\\F=-108\cdot10^{13}\\\boxed{\boxed{F=-1,08\cdot10^{15}\,\text{N}}}[/tex]

Q1 = +16 C
Q2 = -12 C
r = 4 cm = 4×10^(-2) m
k = 9×10^9 Nm^2/C^2
...........Q1 × Q2
F = k --------------
..................r^2
.......................+16 × (-12)
F = 9×10^9 ---------------------
.......................(4×10^(-2))^2
.................... - 1,92 × 10^2
F = 9×10^9 -------------------
.......................1,6 × 10^(-3)
....... -1,728 × 10^12
F = ---------------------
.........1,6 × 10^(-3)
F = - 1,08 × 10^15 N