[x-6]^2+2]x-6]+3=2............

       (x-6)²+2(x-6)+3=2
 (x-6)(x-6)+2(x-6)+3=2
x²-12x+36+2x-12+3=2
               x²-10x+27=2
            x²-10x+27-2=0
               x²-10x+25=0
            x²-5x-5x+25=0
           x(x-5)-5(x-5)=0
                (x-5)(x-5)=0

x=5

(x - 6)² + 2(x - 6) + 3 = 2
x² - 12x + 36 + 2x - 12 + 3 - 2 = 0
x² - 10x + 25 = 0
(x - 5)(x - 5) = 0
x = 5

Semoga berguna +_+