tolong dijawab ya!!!!!

proyeksi skalar
a*b / |b|
|b| = √4+4+1 = √9=3
maka(-3)1 +4(2)+(-5(-2)/3
-3+8+10 /3
= 15/3 =>>>> 5

proyeksi skalar b ke a
|a|= √9+16+25=√25*2
= 5√2
= b*a/ |a|
= 1(-3)+2(4)+(-5)(-2)/5√2
= 15/5√2
= 3/2 √2

[tex]\displaystyle |\vec{p}|=\left|\frac{\vec{a}\cdot\vec{b}|}{|\vec{b}}\right|\\|\vec{p}|=\left|\frac{a_1b_1+a_2b_2+a_3b_3}{\sqrt{b_1^2+b_2^2+b_3^2}}\right|\\|\vec{p}|=\left|\frac{-3\cdot1+4\cdot2-5\cdot(-2)}{\sqrt{1^2+2^2+(-2)^2}}\right|\\|\vec{p}|=\left|\frac{-3+8+10}{\sqrt{1+4+4}}\right|\\|\vec{p}|=\left|\frac{15}{3}\right|\\\boxed{\boxed{|\vec{p}|=5}}[/tex]

[tex]\displaystyle |\vec{q}|=\left|\frac{\vec{a}\cdot\vec{b}|}{|\vec{a}}\right|\\|\vec{q}|=\left|\frac{a_1b_1+a_2b_2+a_3b_3}{\sqrt{a_1^2+a_2^2+a_3^2}}\right|\\|\vec{q}|=\left|\frac{-3\cdot1+4\cdot2-5\cdot(-2)}{\sqrt{(-3)^2+4^2+(-5)^2}}\right|\\|\vec{q}|=\left|\frac{-3+8+10}{\sqrt{9+16+25}}\right|\\|\vec{q}|=\left|\frac{15}{5\sqrt2}\right|\\\boxed{\boxed{|\vec{q}|=\frac32\sqrt2}}[/tex]