Matematika

Pertanyaan

Akar – akar persanaan kuadrat x 2 + 4 x + K = 0 adalah x 1 dan x 2 . Jika x 12 – x 22 = -32, maka k

2 Jawaban

  • [tex]\displaystyle x_1^2-x_2^2=-32\\(x_1-x_2)(x_1+x_2)=-32\\\left(\pm\frac{\sqrt{D}}{a}\right)\left(-\frac{b}{a}\right)=-32\\\left(\pm\frac{\sqrt{b^2-4ac}}{a}\right)\left(-\frac{b}{a}\right)=-32\\\left(\pm\frac{\sqrt{(-4)^2-4(1)k}}{1}\right)\left(-\frac{4}{1}\right)=-32\\\pm\sqrt{16-4k}=8\\16-4k=64\\-4k=48\\\boxed{\boxed{k=-12}}[/tex]
  • Akar akar Persamaan Kuadrat
    x² + 4x + k = 0
    a= 1 , b = 4 , c = k
    x₁ + x₂ - b/a= -4/1 = - 4
    x₁ x₂ = c/a= k/1 = k
    .
    x₁² - x₂² = 32
    (x₁+x₂)(x₁- x₂)  = 32
    -4(x₁- x₂) = 32
    (x₁- x₂) = - 8
    (x₁-x₂)² = (-8)² = 64
    (x₁+x₂)²- 4(x₁x₂) = 64
    (-4)² - 4(k) = 64
    16 -4k = 64
    -4k = 48
    k = -12

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