Tolong dijawab kaka', terimakasih

[tex]\displaystyle y=\sqrt{3x^4+2x}\\y=(3x^4+2x)^\frac12\\\\y'=\frac12\cdot(12x^3+2)(3x^4+2x)^{\frac12-1}\\y'=(6x^3+1)(3x^4+2x)^{-\frac12}\\\boxed{\boxed{y'=\frac{6x^3+1}{\sqrt{3x^4+2x}}}}[/tex]