mohon bantuan nya lagi
Matematika
farhanmahe
Pertanyaan
mohon bantuan nya lagi
2 Jawaban
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1. Jawaban Ayundaa9
ini nomer 17 semoga membantu2. Jawaban arsetpopeye
17) QP^-1 = (2 ... 1)
.................... (4 ... 3)
Q = (2 ... 1) P
....... (4 ... 3)
Q = (2 ... 1) (1 ... 2) = (2 + 3 ... 4 + 5) = (5 ..... 9)
....... (4 .. 3) (3 .. 5) .. (4 + 9 .. 8 + 15) .. (13 .. 23)
26) g(x) = (3 - 2f(x))^3
g'(x) = 3(3 - 2f(x))^2 . -2f'(x)
g'(0) = 3(3 - 2f(0))^2 . -2 f'(0)
= 3(3 - 2(3))^2 . -2 (2)
= 3 (3 - 6)^2 . -4
= 3 . 9 . -4
= -108Pertanyaan Lainnya