Matematika

Pertanyaan

1. 5(x)^4+7(x)^2+3(x)+1. untuk x=-3
2.(a)^3-(a)^2-2(a), untuk a=2
3. (t)^5+(t)^4-2(t)^3+2(t)-1, untuk t=-1/3
4.2(x)^7-3(x)^4+2(x)^2-5(x)+10, untuk X=-2

hitunglah nilai sukubanyak dg Subtitusi dan Skema

2 Jawaban

  • 1. = 5(-3)^4+7(-3)^2+3(-3)+1
    = 5(81) +7(9) - 9 +1
    = 405+63 -9+1
    = 460

    2.= (2)^3-(2)^2 - 2(2)
    = 8 - 4 - 4
    = 0

    3.= (-1/3)^5+(-1/3)^4-2(-1/3)^3+2(-1/3)-1
    = -1/243 + 1/81 +2/27 -2/3 - 1
    = -1/243 + 3/243 + 18/243 - 162/243 - 243/243
    = -385/243

    4.= 2(-2)^7 -3(-2)^4+2(-2)^2-5(-2)+10
    = 2(-128) -3(16) + 2(4) +10+10
    = -256 - 48 +8+20
    = -276
  • 1) 5(x)^4 + 7(x)^2 + 3(x) + 1 x = -3
    = 5(-3)^4 + 7(-3)^2 + 3(-3) + 1
    = 5(81) + 7(9) + 3(-3) + 1
    = 405 + 63 - 9 + 1
    = 460
    2) (a)^3 - (a)^2 - 2(a) a = 2
    = (2)^3 - (2)^2 - 2(2)
    = 8 - 4 - 4
    = 0
    3) (t)^5 + (t)^4 - 2(t)^3 + 2(t) - 1 t = -1/3
    = (-1/3)^5 + (-1/3)^4 - 2(-1/3)^3 + 2(-1/3) - 1
    = - 1/243 + 1/81 - 2(- 1/27) - 2/3 - 1
    = -385/243
    4) 2(x)^7 - 3(x)^4 + 2(x)^2 - 5(x) + 10 x = -2
    = 2(-2)^7 - 3(-2)^4 + 2(-2)^2 - 5(-2) + 10
    = 2(-128) - 3(16) + 2(4) - 5(-2) + 10
    = - 256 - 48 + 8 + 10 + 10
    = -276
    kalau ada yg ga paham tanya ya dek :)


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