^3logx + logn6x - log2x - log24 =0 maka nilai x =?

Bab Logaritma
Matematika SMA Kelas X

³log x + log 6x - log 2x - log 24 = 0
³log x = - log (6x / (2x . 24))
³log x = - log (1/8)
³log x = - log 8⁻¹
³log x = - . (-1) . log 8
³log x = log 8
x = 3^(log 8)

x = 3^(0,903)
x = 2,69