Matematika

Pertanyaan

Nilai lim x→1 (x²- 1) sin (2x - 2)/ -2 sin² (x - 1) =....

1 Jawaban

  • LImit trigonometri

    lim(x->1) (x² -1) sin (2x-2) / -2 sin² (x-1) =
    = lim(x->1) (x+1) (x-1) sin 2(x-1) /. -2 sin (x-1). sin (x-1)
    = lim(x->1) (x+1). (x-1) . 2(x-1) / -2 (x-1)(x-1) .....*coret (x-1)nya
    = lim(x->1) (x+1)(2) / -2
    x = 1 --> limit = (1+1)(2)/ (-2) = 4/-2 = - 2

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