tolong di jwb no 4 yaa plisss makasih❤

Bab Logaritma
Matematika SMA Kelas X

^(√6)log 9 x log 36 - 49 . log (1/7)
= ^(√6)log 36 x log 9 - 49 . log 7⁻¹
= ^(6^(1/2))log 6² x log 9 - 49 . (-1) . log 7
= (2 : 1/2) ⁶log 6 x log 9 + 49 x log 7
= 4 x 1 x 0,954 + 49 x 0,845
= 3,816 + 41,405
= 45,221

4) dibalik
log 36 × ^√6log 9 - 49 log 7^-1
= log 6^2 × ^6^½log 9 - 49(-1) log 7
= 2 log 6 × (2) ^6log 9 + 49 log 7
= 2(2) log 9 + 49 log 7
= 4 log 9 + 49 log 7
= log 9^4 + log 7^49
= log (9^4 . 7^49)

^ tanda pangkat