Persamaan nilai mutlak A. (2y+5)=(7-2y) B.(4x-3)=-(2x-1)
Matematika
Cay00
Pertanyaan
Persamaan nilai mutlak
A. (2y+5)=(7-2y)
B.(4x-3)=-(2x-1)
A. (2y+5)=(7-2y)
B.(4x-3)=-(2x-1)
2 Jawaban
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1. Jawaban eripane05
1.|2y+5|= |7-2y|
2y+5 = 7-2y
2y+2y = 7-5
y= 2/4 = 1/2
2.|4x-3|= -|2x-1|
=>>> 4x -3 = -2x+1
6x = 4
x= 2/3
Bila maksud anda
|4x-3|=- |2x-1|
Tidak akan mungkin sama karena nilai mutlak pasti bernilai (+) -
2. Jawaban ErikCatosLawijaya
Mapel : Matematika
Kelas : X SMA
Bab : Mutlak
Pembahasan :
|2y + 5| = |7 - 2y|
(2y + 5)² = (7 - 2y)²
(2y + 5)² - (7 - 2y)² = 0
(4y - 2)(12) = 0
48y - 24 = 0
48y = 24
y = 1/2
Hp : {1/2}
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|4x - 3| = -|2x - 1|
|4x - 3| + |2x - 1| = 0
4x - 3 + 2x - 1 = 0
6x - 4 = 0
6x = 4
x = 4/6
x = 2/3
Hp : {2/3}
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