Matematika

Pertanyaan

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jabarkanlah setiap bentuk perkalian berikut dengan menggunakan skema!
•(2a-5)(2a+9)
•(15-4y)(15+4y)
•(9+12y)(9-12y)
•(x²+y²)(x²-y²)
•(x²+5x)(x²-10y
•(4x²-2y)(4x²-5y)
•(5x²-8x)(5x²+8)
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1 Jawaban

  • Mapel : Matematika
    Kelas : VII SMP
    Bab : Aljabar dasar

    Rumus dasar :
    1. (a - b)(a + b) = a² - b²
    2. (a + b)² = a² + 2ab + b²
    3. (a - b)² = a² - 2ab + b²

    Pembahasan :
    (2a - 5)(2a + 9)
    = (2a)(2a) + (2a)(9) + (-5)(2a) + (-5)(9)
    = 4a² + 18a - 10a - 45
    = 4a² + 8a - 45

    (15 - 4y)(15 + 4y)
    = 15² - (4y)² ——» Use Rumus 1
    = 225 - 16y²

    (9 + 12y)(9 - 12y)
    = 9² - (12y)² ——» Use Rumus 1
    = 81 - 144y²

    (x² + y²)(x² - y²)
    = (x²)² - (y²)²
    = x⁴ - y⁴

    (x² + 5x)(x² - 10y)
    = (x²)² + (x²)(-10y) + (5x)(x²) + (5x)(-10y)
    = x⁴ - 10x²y + 5x³ - 10xy

    (4x² - 2y)(4x² - 5y)
    = (4x²)² + (4x²)(-5y) + (-2y)(4x²) + (-2y)(-5y)
    = 16x⁴ - 20x²y - 8x²y + 10y²
    = 16x⁴- 28x²y + 10y²

    (5x² - 8x)(5x² + 8)
    = (5x²)² + (5x²)(8) + (-8x)(5x²) + (-8x)(8)
    = 25x⁴ + 40x² - 40x³ - 64x²
    = 25x⁴ - 40x³ - 16x²

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