diketahui ²log3=a dan ³log5=b hitunglah ^10Log 81? makasih...

²log₃ . ³log₅ = ²log₅ = ab

¹⁰log 81 = ¹⁰log 3⁴ = 4 . ²log 3 / ²log 2 + ²log 5 = 4a / (1 + ab) ⇒ Jawab

10log81 = (³log 81)/(³log 10)
= (³log 3^4) / (³log 2.5)
= 4 . ³log 3 / (³log 2 + ³log 5)
= 4 / (1/a + b) . a/a
= 4a / (1 + ab)