Matematika

Pertanyaan

KUIS MATEMATIKA
Kode: 01-1-2
KUIS MATEMATIKA Kode: 01-1-2

2 Jawaban

  • Materi: Persamaan dan Fungsi Kuadrat
    Gambar lampiran jawaban ShanedizzySukardi
  • ax^2 + bx + c = 0 akar-akarnya saling berlawanan artinya :
    b = 0 => (x1 = -x2 => x1 + x2 = -b/a => -x2 + x2 = -b/a => 0 = b)

    (x^2 - bx)/(ax - c) = (m - 1)/(m + 1)
    (x^2 - bx)(m + 1) = (ax - c)(m - 1)
    mx^2 + x^2 - bmx - bx = amx - ax - cm + c
    mx^2 + x^2 - bmx - bx - amx + ax + cm - c = 0
    (m + 1)x^2 - (bm + b + am - a)x + (cm - c) = 0
    Akar-akarnya berlawanan => b = 0
    - (bm + b + am - a) = 0 ===> kali (-1)
    bm + b + am - a = 0
    bm + am = a - b
    m(a + b) = a - b
    m = (a - b)/(a + b)