Sebuah benda diletakkab 2cn dari lensa objektif. Jaraj fokus lensa objektif 1,5 cm, jarak lensa okuler 2,5cm. (Sn:25cm) Berapakah perbesaran bayangan?

Sobj= 2cm
Fobj= 1,5cm
Sok= 2,5cm
sn= -s'ok= 25cm

1/fob = 1/sob + 1/sob'
1/1,5 = 1/2 + 1/sob'
1/sob' = 2/3 - 1,5/3 = 5/30 = 1/ 6
sob' = 6 cm

1/fok= 1/sok-1/s'ok
1/fok= 1/2,5-1/ 25
1/fok= 10/25- 1/25 =9/25
fok= 25/9

Ma= s'ob/sob (sn/fok+1)
= 6/ 2 (25/(25/9) +1)
= 3 (9+1) = 30x