Tolong yaa sama caranya jugaa

6. Dik f(g(x)) = 8x^2+24x+15/2x+3 = h(x)
g(x)^-1 = x-3/2
f(x) = h(x)og(x)^-1
f(x) = 8(x-3/2)^2+24(x-3/2)+15 / 2(x-3/2)+3
f(x) = 8(x^2-6x+9/4) + 12x-36 + 15 / x-3+3
f(x) = 2x^2-12x+18 + 12x-36 + 15 / x
f(x) = 2x^2 - 3 / x
f(1/2) = 2(1/2)^2 - 3 / 1/2
f(1/2) = 2 (2(1/4)-3) = 1-6 = -5
7. 4/√x+3 ≤ √x-3 (dikuadratkan)
16 / x+3 ≤ x-3
16 ≤ x^2-9 (jadikan ruas kanan 0)
16 -x^2+9 ≤ 0
-x^2+25 ≤ 0 = x^2-25 ≥ 0
(x-5)(x+5) ≥ 0 {x≥5 / x≤-5}
syarat akar = ≥0
x+3 ≥ 0
x ≥ -3
x-3 ≥ 0
x ≥ 3
Irisannya adalah x≥5