point + follow untuk soal ini:)

[tex]\displaystyle PERSAMAAN \ GARIS \ SINGGUNG \ [XI] \\ y = (x^2+1)^3(x^4+1)^2 \xrightarrow \ x = 1 \\ y = 32 \xrightarrow \ (1, 32) \\ Mis : u = (x^2+1)^3 \xrightarrow \ u' = 3(2x)(x^2+1)^2 \\ v = (x^4+1)^2 \xrightarrow \ v' = 2(4x^3)(x^4+1) \\ y' = 3(2x)(x^2+1)^2 . (x^4+1)^2 + (x^2+1)^3 . 2(4x^3)(x^4+1) \\ A \ FEW \ MOMENTS \ LATER \\ y' = 2x(x^2+1)^2(x^4+1)(7x^4+4x^2+3) \xrightarrow \ x = 1 \\ y' = 224 \\ \\ y-y1 = m(x-x1) \\ y-32 = 224(x-1) \\ y = 224x - 192 \\ Memotong \ sumbu-x \xrightarrow \ y = 0 \\ 0 = 224x - 192 \\ x = \frac{192}{224} \\ x = \frac{6}{7} \\ \\ So, \ the \ answer \ is \ ( \frac{6}{7}, 0) \ (A) \xrightarrow \ Answer [/tex]