Matematika

Pertanyaan

integral p(1+p^2)^1/3 dp

1 Jawaban

  • intergral substitusi

    t = 1+p²
    dt= 2p dp
    p dp  =¹/₂  dt
    ∫ p(1+p²)¹/³ dp = ∫¹/₂   t¹/³ dt = ¹/₂ (³/₄) (t)⁴/³ + c
    =³/₈ t∛t + c
    = ³/₈  (1+p²) ∛(1+p²) + c

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