Matematika

Pertanyaan

integral 4t/(t^2-1)^2 dt

1 Jawaban

  • Int 4t/(t^2 - 1)^2 dt
    = Int 4t (t^2 - 1)^-2 dt

    Misal
    u = t^2 - 1
    du = 2t dt => dt = du/2t

    = Int 4t . u^-2 . du/2t
    = Int 2 u^-2 du
    = 2/-1 u^-1 + C
    = -2/u + C
    = -2/(t^2 - 1) + C

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