Matematika

Pertanyaan

Jika f(x)=2x-√2 dang(x)= x^2-2 maka {g.f)(-√2)

1 Jawaban

  • f(x) = 2x - √2
    g(x) = x² - 2

    (gof)(-√2)=?

    (gof)(x) = g(f(x))
    =(2x - √2)² - 2
    = 4x² - 4x√2 + 2 - 2
    = 4x² - 4x√2

    (gof)(-√2) = 4(-√2)² - 4(-√2)(√2)
                    = 4 × 2 - 4 × (-2)
                    = 8 - (-8)
                    = 8 + 8
                    = 16

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