cara substitusi : 1. -y + 6x = 1 3x + y = 18 2. y = 2x - 2 4x + 2y = 5 3. x + 2y = 4 -x + 3y = 1 cara eliminasi 8x + 3y = 40 -8x + 5y = 16 tolong sama cara meng
Matematika
Shinta06
Pertanyaan
cara substitusi :
1. -y + 6x = 1
3x + y = 18
2. y = 2x - 2
4x + 2y = 5
3. x + 2y = 4
-x + 3y = 1
cara eliminasi
8x + 3y = 40
-8x + 5y = 16
tolong sama cara mengerjakannya yahh ???
1. -y + 6x = 1
3x + y = 18
2. y = 2x - 2
4x + 2y = 5
3. x + 2y = 4
-x + 3y = 1
cara eliminasi
8x + 3y = 40
-8x + 5y = 16
tolong sama cara mengerjakannya yahh ???
2 Jawaban
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1. Jawaban bryancolin
1.-y+6x=1, 3x+y=18
6x-1=y
3x+y=18 6x-1=y
3x+6x-1=18 6(19/9)-1=y
9x=18+1 38/3-1=y
9x=19 35/3=y
x=19/9 -
2. Jawaban nianty
subsitusi
1. -y + 6x = 1
y = 6x - 1
*3x + y = 18
3x + 6x - 1 = 18
9x -1 = 18
9x = 18 + 1
x = 19/9
*y = 6x - 1
y = 6 ( 19/9 ) - 1
y = 35/3