Cara penyelesaian no 3&4 gmn ya? Tlg bantu hehe:)

3) (f o g)(x) = 4^(x + 1)
f(g(x)) = 4^x . 4
f(2^2x) = (2^2x) . 4
Misal 2^2x = p
f(p) = p . 4
f(3) = 3 . 4 = 12

4)
kelipatan 6
6, 12, 18, ..... , 2010
Un = 6n = 2010 => n = 335
Sn = n/2 (a + Un) = 335/2 (6 + 2010) = 335/2 (2016) = 337.680

Kelipatan 6 dan kelipatan 5 = kelipatan 30
30, 60, 90, 120, ..., 2010
Un = 30n = 2010 => n = 67
Sn = n/2 (a + Un) = 67/2 (30 + 2010) = 67/2 (2040) = 68.340

Jumlah kelipatan 6 dan tidak kelipatan 5
337.680 - 68.340 = 269.340