ini bagaimana caranya mohon bantu

Mapel : Matematika
Kelas : X SMA
Bab : Logaritma

Pembahasan :
(x - 1)'log (x² + 6) = (x - 1)'log 5x
x² + 6 = 5x
x² - 5x + 6 = 0
(x - 3)(x - 2) = 0
x = 2
x = 3

Hp : {2,3}

Jawaban : C

(x - 1)'log (x^2 + 6) = (x - 1)'log 5x
(x - 1)'log / (x - 1)'log {x^2+6} = 5x
x^2 + 6 - 5x = 0
x^2- 5x + 6 = 0
(x - 3)(x - 2) = 0
x = 2 atau x = 3

Jd hp nya {2,3} C