Tentukan aljabar: 1. (2x+3) (3x-5)= 2. (3a pangkat2 + 5b pangkat 2) (a pangkat 2 - 5b pangkat 2) =

1. (2x+3) (3x-5) =
6x^2 -10x + 9x - 15 =
6x^2 - x - 15 = 0

2. (3a^2 +5b^2) (a^2 - 5b^2)
3a^4 - 15(ab)^2 + 5(ab)^2 - 5b^4
3a^4 - 10(ab)^2 - 5b^4

3. (4p - 5q)^2 = 16p^2 + 25q^2 - 40pq

1. (2x+3)(3x-5)
= 2x.3x +2x.(-5) +3.3x + 3(-5)
= 6x^2 -10x +9x - 15
= 6x^2 - 1x - 15

2.(3a^2 +5b^2)(a^2 - 5b^2)
= 3a^2.a^2 + 3a^2 .(-5b^2) + 5b^2 .a^2 + 5b^2.(-5b^2)
= 3a^4 - 15a^2b^2 + 5a^2b^2 - 25 b^4
=3a^4 - 10a^2b^2 - 25 b^4

3.(4p-5q)^2
= (4p-5q)(4p-5q)
= 4p.4p + 4p .(-5q) +(-5q).4p +(-5q)(-5q)
= 16p^2 -20pq - 20pq +25q^2
= 16p^2 -40pq +25q^2

^ = dibaca pangkat