Mohon bantuan nya soal limit ini

limit = - 1/2
di lampiran

[tex]\displaystyle \lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}\cdot\frac{\sqrt x+\sqrt{2x-1}}{\sqrt x+\sqrt{2x-1}}\\\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\lim_{x\to1}\frac{x-2x+1}{(x-1)(\sqrt x+\sqrt{2x-1})}\\\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\lim_{x\to1}\frac{1-x}{(x-1)(\sqrt x+\sqrt{2x-1})}\\\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\lim_{x\to1}\frac{-1}{\sqrt x+\sqrt{2x-1}}[/tex]
[tex]\displaystyle \lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\frac{-1}{\sqrt 1+\sqrt{2(1)-1}}\\\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=\frac{-1}{1+1}\\\boxed{\boxed{\lim_{x\to1}\frac{\sqrt x-\sqrt{2x-1}}{x-1}=-\frac{1}{2}}}[/tex]