bantuin no 49 beserta caranya ya

Diket :
Massa Be, mBe = 9,01218 sma
Massa α, mα = 4,00260 sma
Massa C, mC = 12,00000 sma
Massa n, mN = 1,00866 sma
Jika 1 sma = 931 MeV

Tanya :
Energi, E = __?

Jawab :
Step 1
----------
Cari defek massa dulu ya,
Δm = (mBe + mα) - (mC + mN)
Δm = (9,01218 + 4,00260) - (12,00000 + 1,00866)
Δm = (13,01478) - (13,00866)
Δm = 0,00612 sma

Step 2
---------
Maka energi yg dilepas sebesar,
E = Δm x 931 MeV
E = 0,00612 x 931 MeV
E = 5,69772 MeV
Dibulatkan menjadi
E = 5,7 MeV

Jawaban : D

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